// Working solution to the same Number Bases problem.
#include <iostream>
using namespace std;

int main() {
    int n, bx;
    cin >> n >> bx;

    long long X = 0;

    for (int i = 0; i < n; i++) {
        int digit;
        cin >> digit;

        X = X * bx + digit;
    }

    int m, by;
    cin >> m >> by;

    long long Y = 0;

    for (int i = 0; i < m; i++) {
        int digit;
        cin >> digit;

        Y = Y * by + digit;
    }

    if (X < Y)
        cout << "<";
    else if (X > Y)
        cout << ">";
    else
        cout << "=";

    return 0;
}